Table of contents

If you want to draw a circular path then it easy enough to generate the points, in the XY plane, for this using

```
var path = [];
for(var theta = 0; theta < 2 * Math.PI; theta +=deltaTheta ) {
path.push(new BABYLON.Vector3(radius * Math.cos(theta), radius * Math.sin(theta), 0));
```

When you are of a mind to do it you can work out some quite complex paths by hand.

What follows is how to draw some mathematical curves by using the Babylon.js *Curve3* object, from which you can extract the array of points you need to draw lines, ribbons, tubes and extruded shapes.

The general form is

```
var curve = BABYLON.Curve3.Create.CURVETYPE(parameters);
```

http://en.wikipedia.org/wiki/B%C3%A9zier_curve#Quadratic_curves

```
var bezier2 = BABYLON.Curve3.CreateQuadraticBezier(origin, control, destination, nb_of_points);
```

**origin**:*Vector3*the origin point,**control**:*Vector3*the control point,**destination**:*Vector3*the destination point,**nb_of_points**:*number*number of points wanted in the path array.

This static method returns an instance of *Curve3*.

Just use the Curve3 *getPoints()* method to fill your array : *getPoints()* returns an array of successive *Vector3*.

The *length()* method returns the curve length.

```
var path = bezier2.getPoints();
var l = bezier2.length();
```

http://en.wikipedia.org/wiki/B%C3%A9zier_curve# Higher-order_curves

```
var bezier3 = BABYLON.Curve3.CreateCubicBezier(origin, control1, control2, destination, nb_of_points)
```

**origin**:*Vector3*the origin point,**control1**:*Vector3*the first control point,**control2**:*Vector3*the second control point,**destination**:*Vector3*the destination point,**nb_of_points**:*number*the wanted final curve number of points in the array.

This static method returns an instance of *Curve3*.

Just use the Curve3 *getPoints()* method to fill your array : *getPoints()* returns an array of successive *Vector3*.

The *length()* method returns the curve length.

```
var path = bezier3.getPoints();
var l = bezier3.length();
```

http://en.wikipedia.org/wiki/Cubic_Hermite_spline

```
var hermite = BABYLON.Curve3.CreateHermiteSpline(p1, t1, p2, t2, nbPoints);
```

**p1**:*Vector3*the origin point,**t1**:*Vector3*the origin tangent vector,**p2**:*Vector3*the destination point,**t2**:*Vector3*the destination tangent vector,**nbPoints**:*number*the wanted final curve number of points in the array.

This static method returns an instance of *Curve3*.

Just use the Curve3 *getPoints()* method to fill your array : *getPoints()* returns an array of successive *Vector3*.

The *length()* method returns the curve length.

```
var path = hermite.getPoints();
var l = hermite.length();
```

https://en.wikipedia.org/wiki/Cubic_Hermite_spline#Catmull.E2.80.93Rom_spline

```
var nbPoints = 20; // the number of points between each Vector3 control points
var points = [vec1, vec2, ..., vecN]; // an array of Vector3 the curve must pass through : the control points
var catmullRom = BABYLON.Curve3.CreateCatmullRomSpline(points, nbPoints);
```

**points**:*Vector3*an array of Vector3 (the control points) the curve will pass through,**nbPoints**:*number*the wanted curve number of points between each control point.

*Curve3*.

Just use the Curve3 *getPoints()* method to fill your array : *getPoints()* returns an array of successive *Vector3*.

The *length()* method returns the curve length.

```
var path = catmullRom.getPoints();
var l = catmullRom.length();
```

You can also make your own Curve3 object from a simple array of successive Vector3.

Why would you do this and not just use the points to draw a line?

Because the *Curve3* object has a useful method, the *continue()* method, that allows you place the start of one *Curve3* onto the end of another *Curve3* without any calculations to match the start and end points of the curves.

Create an array of Vector3 along a simple sinus curve.

```
var mySinus = [];
for (var i = 0; i < 30; i++) {
mySinus.push( new BABYLON.Vector3(i, Math.sin(i / 10), 0) );
}
var mySinusCurve = new BABYLON.Curve3(mySinus);
```

You would like to continue your *mySinus* curve with a *bezier3* curve and then join on a *bezier2*.

```
var myFullCurve = mySinusCurve.continue(bezier3).continue(bezier2);
```

The *continue()* method returns a new *Curve3* object and leaves *mySinusCurve3*, *bezier3* and *bezier2* unchanged.

If you then need to draw the curve or use it for whatever you want you just get the array of points with the *getPoints()* method. This method simply returns an array of successive *Vector3*.

```
var path = myFullCurve.getPoints();
var extruded = BABYLON.Mesh.ExtrudeShape("extrudedShape", shape, path, 1, 0, scene);
```

If you need then to know the curve length, just use the * length()* method.

```
var l = myFullCurve.length();
```

Playgound Example - Joined Curves -

Here is an example where a Hermite Spline is used to close smoothly a concatenation of two Bezier curves. As the spline is closing the curves the first and last points of the open continued curve need to be read from the array.

- The first and last points of the concatenation are used as last and first point of the Hermite spline.
- The first and last segments of the concatenation are used as last and first tangent vectors of the Hermite. Since these segment are quite small, they are scaled according to the concatenation
*length*so the longer the concatenation, the more curved the spline.

```
// two concatened cubic Bezier
var cubicA = BABYLON.Curve3.CreateCubicBezier(vA0, vA1, vA2, vA3, 50);
var cubicB = BABYLON.Curve3.CreateCubicBezier(vB0, vB1, vB2, vB3, 50);
var continued = cubicA.continue(cubicB);
// initial Hermite values from continued first and last segments
var t = continued.length() / 2; // tangent scale factor
var points = continued.getPoints();
var p1 = points[points.length - 1]; // last continued point = first hermite point
var t1 = (p1.subtract(points[points.length - 2])).scale(t); // last segment scaled = hermite tangent t1
var p2 = points[0]; // first continued point = last hermite point
var t2 = (points[1].subtract(p2)).scale(t); // first segment scaled = hermite tangent t2
var hermite = BABYLON.Curve3.CreateHermiteSpline(p1, t1, p2, t2, 50);
continued = continued.continue(hermite);
// finally drawing a smooth closed curve
var closedCurve = BABYLON.Mesh.CreateLines("closed", continued.getPoints(), scene);
```

The orange and yellow curves are the original Bezier curves.

In light blue, these two curves are continued each other and a hermite curve is also added in continuation to close the path.

How To Create Parametric Shapes